Timeline for Electric field in a shell in asymmetric situation
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 2, 2021 at 15:24 | comment | added | Parth Bhardwaj | I don't understand how can we say that if flux of electric field is zero then electric field is also zero, since the situation is asymmetric. | |
| Jan 2, 2021 at 15:15 | comment | added | Yejus | Simply use Gauss' law: $\nabla \cdot \mathbf{E} = \rho_{free}/\epsilon$. There are no free charge-carriers inside, so $\nabla \cdot \mathbf{E} = \mathbf{0}.$ This holds for any infinitesimally small area inside the conductor, so $\mathbf{E} = \mathbf{0}$. | |
| Jan 2, 2021 at 15:10 | comment | added | Parth Bhardwaj | Yes I understand that field on the shell is zero because charge carriers can orient themselves in response to the field. But I don't understand why there won't be any field inside the shell( the volume where there is vacuum and no charge carriers). | |
| Jan 2, 2021 at 15:01 | history | answered | Yejus | CC BY-SA 4.0 |