Timeline for How to find position vector in Kepler orbit?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 1, 2021 at 22:50 | comment | added | Adam Zalcman | I'm glad I could help. Happy new year! | |
| Jan 1, 2021 at 22:44 | vote | accept | Chtholly | ||
| Jan 1, 2021 at 22:44 | comment | added | Chtholly | Thank you for your reply. That was actually what I thought originally, but I was wondering if there are any approach could avoid doing such rotation. anyway, thank you very much and happy new year. | |
| Jan 1, 2021 at 22:37 | comment | added | Adam Zalcman | In this case, you can first follow the answer to obtain $(x, y, z)=(r\cos\theta, r\sin\theta, 0)$ coordinates in the frame whose $xy$ plane lies in the orbital plane. Next, you can rotate these coordinates into the coordinate frame you prefer. This leaves the problem of finding the appropriate rotation. That depends on what data you are given. For example, if you're given angular momentum vector (and not just its magnitude) then you can exploit the fact that the vector points along the $z$ axis in the first frame. | |
| Jan 1, 2021 at 22:19 | comment | added | Chtholly | No, it is not the case. The only constraint is center mass sits in origin (0,0,0). The position and velocity vector could point to any direction. i.e., angular momentum does not necessarily perpendicular to x-y plane. | |
| Jan 1, 2021 at 22:04 | comment | added | Adam Zalcman | The answer makes the assumption that you're trying to obtain a position vector in a Cartesian frame whose $xy$ plane lies in the plane of the orbit and so the third coordinate (e.g. $z$) can be assumed to be zero at all times. Are you saying this is not the case? If so, what coordinate frame would you like your position vector to be expressed in? | |
| Jan 1, 2021 at 21:55 | comment | added | Chtholly | Thank you for your reply. This is correct, but those equation does not accommodate yaw, roll and pitch of the orbit. How do I transform this result in 'standard reference frame' into any predefined orbit? | |
| Jan 1, 2021 at 20:05 | history | answered | Adam Zalcman | CC BY-SA 4.0 |