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Jan 1, 2021 at 14:07 history edited Qmechanic CC BY-SA 4.0
edited tags; edited title
Jan 1, 2021 at 12:16 answer added secavara timeline score: 6
Dec 31, 2020 at 15:47 vote accept goalgetter666
Dec 31, 2020 at 15:44 comment added TBissinger Sorry, I misread your statement. You're obviously right. Deleted my comment.
Dec 31, 2020 at 15:40 comment added secavara @TBissinger Sure, I was pointing to the fact that the expansion in your answer will look more natural in terms of $\alpha$, and that, for a specific value, the expansion is trivial.
Dec 31, 2020 at 15:29 comment added secavara Notice that you are free to set $A = \frac{\alpha M \Omega}{\hbar}$, based on dimensional analysis, with $\alpha$ a dimensionless quantity. If $\alpha = 1$, your state matches the ground state, and its time evolution is just $|\Psi\rangle = \exp\left(-i \frac{t E_0}{\hbar}\right)|0\rangle = \exp\left(-i \frac{t \Omega}{2}\right)|0\rangle$.
Dec 31, 2020 at 15:29 answer added TBissinger timeline score: 5
Dec 31, 2020 at 14:57 review Close votes
Jan 6, 2021 at 3:04
Dec 31, 2020 at 14:53 history edited BioPhysicist
edited tags
Dec 31, 2020 at 14:15 history asked goalgetter666 CC BY-SA 4.0