Timeline for Does Work become state function in an Isothermal Process and what are other processes in which it happens?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Dec 31, 2020 at 16:27 | comment | added | Bob D | Let's find out. | |
| Dec 31, 2020 at 16:20 | comment | added | Chet Miller | @BobD Well, this is just your judgment. What does the OP say? | |
| Dec 31, 2020 at 16:11 | comment | added | Bob D | Yes you proved it in the example for a reversible vs irreversible isothermal process, but I feel you didn't give the knockout punch, which is to explicitly state that it proves work is not a state function. Moreover, to state that work is never a state function regardless of the process. | |
| Dec 31, 2020 at 15:59 | comment | added | Chet Miller | @BobD To prove that the OP is wrong, all that needs to be done is provide an example of two different isothermal paths between the same two isothermal equilibrium end states that gives different values for the amount of work. This is done in the example I provided in which the expansion work for the reversible path is greater than for a specified irreversible work. | |
| Dec 31, 2020 at 15:00 | comment | added | Bob D | But the OP keeps insisting that work can be a state function. See comments below. You haven't addressed that. | |
| Dec 31, 2020 at 13:10 | history | edited | Chet Miller | CC BY-SA 4.0 |
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| Dec 30, 2020 at 19:05 | history | answered | Chet Miller | CC BY-SA 4.0 |