Timeline for Navier-Stokes system
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 14, 2015 at 22:09 | vote | accept | Iuli | ||
| Aug 16, 2015 at 19:31 | answer | added | jjack | timeline score: 1 | |
| Aug 16, 2015 at 19:18 | comment | added | jjack | The time derivative is the (u⋅∇)u term. The partial derivative with respect to time is missing, which means the flow is steady. | |
| Aug 16, 2015 at 18:53 | history | protected | Qmechanic♦ | ||
| Aug 16, 2015 at 18:51 | answer | added | Andrew | timeline score: 2 | |
| Apr 25, 2013 at 19:22 | comment | added | ucsky | That not the conventional Navier-Stokes system because it's missing the time derivative. | |
| Apr 17, 2013 at 16:05 | answer | added | jadelord | timeline score: 1 | |
| Apr 8, 2013 at 0:31 | history | edited | tpg2114 |
edited tags
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| Apr 7, 2013 at 21:44 | answer | added | Isopycnal Oscillation | timeline score: 2 | |
| Apr 7, 2013 at 21:43 | answer | added | Dmist | timeline score: 0 | |
| Apr 7, 2013 at 21:13 | comment | added | Sklivvz | Can you restrict this to a single answerable question? | |
| Apr 7, 2013 at 21:04 | comment | added | Iuli | if $(u \cdot \nabla)u=0$ then the system won't be slow ? | |
| Apr 7, 2013 at 21:02 | comment | added | Bernhard | This is all explained in the Wikipedia article about the Navier-Stokes equations. Can you indicate what it is, that is not clear about this? | |
| Apr 7, 2013 at 21:01 | review | First posts | |||
| Apr 7, 2013 at 21:13 | |||||
| Apr 7, 2013 at 20:50 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
added link
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| Apr 7, 2013 at 20:46 | history | asked | Iuli | CC BY-SA 3.0 |