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Timeline for How does gradient give $g$?

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Dec 14, 2020 at 17:49 comment added Karol Unfortunately, for the force $\propto 1/r^2$ it works (more or less, because the sign is wrong) but when you consider other conservative forces, e.g. Hooke's Law $F=-kx$ what shall you do? Potential energy is then $-\int (-kx) dx = kx^2/2$
Dec 14, 2020 at 14:05 comment added protectgoodlivingbeingask As I am new to calculus could you please elaborate why I cannot just divide v by r=$\sqrt{x^2+y^2+z^2}$ to get it?
Dec 14, 2020 at 14:04 history answered Karol CC BY-SA 4.0