Timeline for How does gradient give $g$?
Current License: CC BY-SA 4.0
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Dec 14, 2020 at 17:49 | comment | added | Karol | Unfortunately, for the force $\propto 1/r^2$ it works (more or less, because the sign is wrong) but when you consider other conservative forces, e.g. Hooke's Law $F=-kx$ what shall you do? Potential energy is then $-\int (-kx) dx = kx^2/2$ | |
Dec 14, 2020 at 14:05 | comment | added | protectgoodlivingbeingask | As I am new to calculus could you please elaborate why I cannot just divide v by r=$\sqrt{x^2+y^2+z^2}$ to get it? | |
Dec 14, 2020 at 14:04 | history | answered | Karol | CC BY-SA 4.0 |