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Aug 29 at 17:25 comment added Zo the Relativist It's probably also worth noting that that factor of $\sqrt{-g}$ is there no matter what. It's just 1 in cartesian coordinates in flat space, but would not be if you were in, say, spherical coordinates.
Aug 29 at 16:36 answer added mike stone timeline score: 0
Dec 8, 2020 at 13:39 vote accept Sven2009
Dec 8, 2020 at 13:38 vote accept Sven2009
Dec 8, 2020 at 13:39
Dec 6, 2020 at 18:00 history tweeted twitter.com/StackPhysics/status/1335645228087320576
Dec 6, 2020 at 16:23 answer added Chiral Anomaly timeline score: 4
Dec 6, 2020 at 14:36 comment added Sven2009 @NiharKarve it is $\int d^4 x \sqrt{-g}$?
Dec 6, 2020 at 14:20 history edited Qmechanic CC BY-SA 4.0
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Dec 6, 2020 at 13:53 history asked Sven2009 CC BY-SA 4.0