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Dec 5, 2020 at 20:07 comment added NotMe If we are interested in the mass of an object, which has a constant mass density $\rho$, we will use $M = \int dm = \int \rho dV = \rho \int dV$ and integrate over its volume. Hence, although this expression might not make sense to you, it is very handy for calculations. I personally never cared to0 much for the philosophical aspects in physics, but used the "definitions" which helped me to obtain the solution of my problem.
Dec 5, 2020 at 19:27 history answered Claudio Saspinski CC BY-SA 4.0