Timeline for Why entropy change of reservoir is reversible?
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
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| Dec 21, 2021 at 11:47 | comment | added | Chet Miller | For what we define as an ideal isothermal reservoir, the change in entropy, by definition, is Q/T (or really $\Delta H/T$ for the reservoir). | |
| Dec 21, 2021 at 3:11 | comment | added | Ashok Kumar | Thank you for your explination, if that is the case, lets say heat transfer between two reservoirs is Q1, due to which entropy changed from s1 to s2 in any one of the reservoir. now to get same entropy change we replace it with with reversible heat transfer process. but the amount of heat transfer in reversible process should be greater than irrerversible heat tranfer Q1. Then how can we say change in entropy is Q1/T(temp of reservoir), because Q1 is actual irreversible heat transfer and it cant be equal to reversible heat transfer. | |
| Dec 3, 2020 at 13:39 | history | answered | Chet Miller | CC BY-SA 4.0 |