Timeline for Why entropy change of reservoir is reversible?
Current License: CC BY-SA 4.0
5 events
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| Mar 24 at 6:30 | comment | added | ReasonMeThis | Two points: 1. The amount of heat transfer in the reversible version doesn't have to be greater than Q1, it can be greater, smaller, or the same. 2. We don't say that the change in entropy is Q1/T. This is only true for an infinitesimal amount of heat transfer (dS = dQ/T). For a non-infinitesimal process, we wouldn't even know which T to use, initial, final, or some intermediate one. | |
| Mar 24 at 4:56 | history | edited | ReasonMeThis | CC BY-SA 4.0 |
Added TL;DR section and improved clarity
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| Dec 21, 2021 at 3:11 | comment | added | Ashok Kumar | Thank you for your explination, if that is the case, lets say heat transfer between two reservoirs is Q1, due to which entropy changed from s1 to s2 in any one of the reservoir. now to get same entropy change we replace it with with reversible heat transfer process. but the amount of heat transfer in reversible process should be greater than irrerversible heat tranfer Q1. Then how can we say change in entropy is Q1/T(temp of reservoir), because Q1 is actual irreversible heat transfer and it cant be equal to reversible heat transfer. | |
| Jan 10, 2021 at 19:22 | history | edited | ReasonMeThis | CC BY-SA 4.0 |
added 10 characters in body
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| Dec 3, 2020 at 7:01 | history | answered | ReasonMeThis | CC BY-SA 4.0 |