Timeline for Definition of $PV$ work
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 29, 2020 at 23:36 | vote | accept | Lee Laindingold | ||
| Dec 2, 2020 at 22:14 | comment | added | Chet Miller | Well, on 2nd thought, it depends on what you mean by internal pressure. If you mean pressure calculated from the ideal gas law, then that is correct. If you mean force per unit area exerted by the gas on the boundary with its surroundings, then, if you knew what that value was for an irreversible process, you could use it, but it wouldn't be equal to the pressure calculated from the ideal gas law (or other equation of state). | |
| Dec 2, 2020 at 22:03 | comment | added | Chet Miller | Yes. That is exactly correct. | |
| Dec 2, 2020 at 21:58 | comment | added | Lee Laindingold | "However, this is still equal to the external pressure of the surroundings." Does that mean that, the $P$ in the expression $\int_{V_i}^{V_f}PdV$ always stands for external pressure, and only stands for internal pressure when it is reversible? | |
| Dec 2, 2020 at 14:15 | history | answered | Chet Miller | CC BY-SA 4.0 |