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Nov 25, 2020 at 0:33 comment added Andrew I think this is where I get into trouble logically speaking, since I think this is more or less what Feynman is trying to prove. But here it goes. If we go through an entire cycle, and there were no losses, and we input work into the system, then we ca have returned to exactly the same state we started with. We have to have ended up in a state with more energy, since we input some work into the system. But the premise of this process combining Machines A and B is that it forms a closed loop and we have returned to exactly the same state we started. So we can't have input any work.
Nov 24, 2020 at 22:56 comment added Paul Razvan Berg Hey I deleted both of my previous comments because I realised I fooled myself into thinking I understand why the net work done on this reversible machine is always zero. I don't, although I suspect that the reason is that nobody applies an external force on the system (or if they do it is an infinitesimally small one). Sorry to pester you but can I kindly ask you expound on this?
Nov 24, 2020 at 0:33 history edited Andrew CC BY-SA 4.0
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Nov 24, 2020 at 0:22 history edited Andrew CC BY-SA 4.0
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Nov 24, 2020 at 0:16 history answered Andrew CC BY-SA 4.0