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Mar 31, 2013 at 10:47 comment added Qmechanic Use that different logarithms are proportional $\log_b \rho =\frac{\ln \rho}{\ln b}$.
Mar 31, 2013 at 10:43 history edited Qmechanic CC BY-SA 3.0
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Mar 31, 2013 at 10:25 answer added seb timeline score: 2
Mar 30, 2013 at 22:54 history tweeted twitter.com/#!/StackPhysics/status/318134081164554240
Mar 30, 2013 at 22:50 answer added Dan timeline score: 9
Mar 30, 2013 at 22:34 history asked ZAC CC BY-SA 3.0