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Nov 21, 2020 at 14:31 comment added Andrew Steane Yes, because the standard deviation is an aspect of the probability distribution.
Nov 21, 2020 at 14:12 comment added Σ baryon So I compare the squared $\widetilde{ \psi }(k)$ to the standard gaussian in order to get the uncertainty in k?
Nov 21, 2020 at 14:10 vote accept Σ baryon
Nov 21, 2020 at 14:02 history answered Andrew Steane CC BY-SA 4.0