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Forget about Feynman lectures, what you need here is the convection-diffusion PDE:

$$\frac{\partial c}{\partial t}=\nabla(D\nabla c)-\nabla(\mathbf{v}c)$$

This is essentially a version of the transport equation.

Assuming $D$ and $\mathbf{v}$ to be constant and for the $text{1D}$ case we have:

$$c_t=Dc_{xx}+v c_x$$

Forget about Feynman lectures, what you need here is the convection-diffusion PDE:

$$\frac{\partial c}{\partial t}=\nabla(D\nabla c)-\nabla(\mathbf{v}c)$$

This is essentially a version of the transport equation.

Assuming $D$ and $\mathbf{v}$ to be constant and for the $\text{1D}$ case we have:

$$c_t=Dc_{xx}+v c_x$$

Forget about Feynman lectures, what you need here is the convection-diffusion PDE:

$$\frac{\partial c}{\partial t}=\nabla(D\nabla c)-\nabla(\mathbf{v}c)$$

This is essentially a version of the transport equation.

Forget about Feynman lectures, what you need here is the convection-diffusion PDE:

$$\frac{\partial c}{\partial t}=\nabla(D\nabla c)-\nabla(\mathbf{v}c)$$

This is essentially a version of the transport equation.

Assuming $D$ and $\mathbf{v}$ to be constant and for the $text{1D}$ case we have:

$$c_t=Dc_{xx}+v c_x$$

Forget about Feynman lectures, what you need here is the convection-diffusion equation:

$$\frac{\partial c}{\partial t}=\nabla(D\nabla c)-\nabla(\mathbf{v}c)$$

Forget about Feynman lectures, what you need here is the convection-diffusion PDE:

$$\frac{\partial c}{\partial t}=\nabla(D\nabla c)-\nabla(\mathbf{v}c)$$

This is essentially a version of the transport equation.