Timeline for How do I find the unit vector for the tangent?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 19, 2020 at 7:02 | comment | added | Himanshu | As you can see the particle at C is moving toward the left. So it's obvious to take $\pi$ because the tangent at this point will be towards the left not right. | |
| Nov 19, 2020 at 6:59 | comment | added | Yoxbox | Thank for your help! I only have one question, why at point $C$ $\theta$ is $\pi$ and not $0$? | |
| Nov 19, 2020 at 5:04 | vote | accept | Yoxbox | ||
| Nov 18, 2020 at 20:49 | history | answered | Himanshu | CC BY-SA 4.0 |