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Timeline for Planck distribution integration

Current License: CC BY-SA 4.0

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Nov 12, 2020 at 4:37 comment added G. Smith If I didn’t de-dimensionalize, I had to use the option Method->”DoubleExponential” with NIntegrate[] in Mathematica. Otherwise, I got $0$.
Nov 12, 2020 at 4:24 comment added G. Smith I had no trouble evaluating the integral numerically after de- dimensionalizing it.
S Nov 12, 2020 at 4:13 history suggested Andrew
Added the tags 'statistical-mechanics' and 'computational-physics'
Nov 12, 2020 at 3:18 answer added flippiefanus timeline score: 0
Nov 12, 2020 at 3:18 review Suggested edits
S Nov 12, 2020 at 4:13
Nov 12, 2020 at 3:10 answer added Ali timeline score: 1
S Nov 12, 2020 at 0:21 history suggested Sebastiano CC BY-SA 4.0
Improved view and mathjax
Nov 11, 2020 at 22:15 review Suggested edits
S Nov 12, 2020 at 0:21
Nov 11, 2020 at 22:12 comment added G. Smith You are probably having trouble because you didn’t de-dimensionalize the integral.
Nov 11, 2020 at 22:10 comment added Vincent ISOZ @G.Smith I wrote "seems to fail" and not just "fail". The point is something cause a problem (whatever it is: very likely because of my ignorance).
Nov 11, 2020 at 21:54 comment added G. Smith How could the convergence fail when the integrand becomes exponentially small as $E\to\infty$?
Nov 11, 2020 at 21:48 comment added Vincent ISOZ @G.SmithThe lower limit is not zero because we are interested only on photons that have an energy higher that the first level of ionization of the Hydrogen atom (13.6 eV)
Nov 11, 2020 at 21:47 comment added Vincent ISOZ @G.Smith "i failed" mean that with all my softwares the convergence seems to fail.
Nov 11, 2020 at 21:47 comment added Vincent ISOZ @G.Smith The units are [J] ( the equivalent of 13.6 [eV])
Nov 11, 2020 at 21:05 review Close votes
Nov 26, 2020 at 3:03
Nov 11, 2020 at 20:54 comment added G. Smith Why is the lower limit not zero? Photons of arbitrarily low energy contribute to the number density.
Nov 11, 2020 at 20:48 comment added G. Smith What does “I failed” mean? What prevented you from obtaining a numerical integration?
Nov 11, 2020 at 20:47 comment added G. Smith What are the units of $2.1789\cdot 10^{-18}$?
Nov 11, 2020 at 20:33 review First posts
Nov 11, 2020 at 22:15
Nov 11, 2020 at 20:27 history asked Vincent ISOZ CC BY-SA 4.0