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Nov 18, 2020 at 12:01 vote accept Ansonī Bōdo
Nov 17, 2020 at 12:57 review Close votes
Nov 18, 2020 at 18:59
Nov 17, 2020 at 11:31 answer added A. Bordg timeline score: 1
Nov 13, 2020 at 0:52 answer added Javier timeline score: 0
Nov 12, 2020 at 13:32 answer added Voulkos timeline score: 0
Nov 12, 2020 at 12:58 comment added Valter Moretti The matrix you wrote transforms the column vector $(1,0,0,0)^t$ to $X$. The matrix you are looking for is the inverse of the one you wrote. It transforms $X$ to the temporal unit vector of another reference frame.
Nov 12, 2020 at 12:11 comment added Ansonī Bōdo I agree with you and found that after the first rotation one needs a boost of velocity $v = -\frac{pc}{a}$ in the z-direction to get the job done. However, I'm still curious about the more algebraic proof outlined in my post.
Nov 12, 2020 at 11:05 history edited Qmechanic
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Nov 12, 2020 at 10:55 history edited Ansonī Bōdo
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Nov 10, 2020 at 21:39 comment added Valter Moretti A better strategy is first rotate the spatial coordinates in order to have only the spatial component z nonvanishing, finally use a boost along z.
Nov 10, 2020 at 18:19 review First posts
Nov 10, 2020 at 18:50
Nov 10, 2020 at 18:10 history asked Ansonī Bōdo CC BY-SA 4.0