Timeline for Problem with the proof that for every timelike vector there exists an inertial coordinate system in which its spatial coordinates are zero
Current License: CC BY-SA 4.0
12 events
when toggle format | what | by | license | comment | |
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Nov 18, 2020 at 12:01 | vote | accept | Ansonī Bōdo | ||
Nov 17, 2020 at 12:57 | review | Close votes | |||
Nov 18, 2020 at 18:59 | |||||
Nov 17, 2020 at 11:31 | answer | added | A. Bordg | timeline score: 1 | |
Nov 13, 2020 at 0:52 | answer | added | Javier | timeline score: 0 | |
Nov 12, 2020 at 13:32 | answer | added | Voulkos | timeline score: 0 | |
Nov 12, 2020 at 12:58 | comment | added | Valter Moretti | The matrix you wrote transforms the column vector $(1,0,0,0)^t$ to $X$. The matrix you are looking for is the inverse of the one you wrote. It transforms $X$ to the temporal unit vector of another reference frame. | |
Nov 12, 2020 at 12:11 | comment | added | Ansonī Bōdo | I agree with you and found that after the first rotation one needs a boost of velocity $v = -\frac{pc}{a}$ in the z-direction to get the job done. However, I'm still curious about the more algebraic proof outlined in my post. | |
Nov 12, 2020 at 11:05 | history | edited | Qmechanic♦ |
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Nov 12, 2020 at 10:55 | history | edited | Ansonī Bōdo |
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Nov 10, 2020 at 21:39 | comment | added | Valter Moretti | A better strategy is first rotate the spatial coordinates in order to have only the spatial component z nonvanishing, finally use a boost along z. | |
Nov 10, 2020 at 18:19 | review | First posts | |||
Nov 10, 2020 at 18:50 | |||||
Nov 10, 2020 at 18:10 | history | asked | Ansonī Bōdo | CC BY-SA 4.0 |