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Qmechanic
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circular Circular motion of an object on the floor of equator

Object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of $m,g,r$ and $\omega$?

Many thanks!

circular motion of an object on the floor of equator

Object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of $m,g,r$ and $\omega$?

Many thanks!

Circular motion of an object on the floor of equator

Object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of $m,g,r$ and $\omega$?

objectObject A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of m,g,r$m,g,r$ and ω$\omega$?

Many thanks!

object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of m,g,r and ω?

Many thanks!

Object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of $m,g,r$ and $\omega$?

Many thanks!

Source Link

circular motion of an object on the floor of equator

object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of m,g,r and ω?

Many thanks!