Timeline for If net $F=0$ on a system then KE of the system may change due to internal forces or due to internal work done
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Nov 6, 2020 at 5:06 | vote | accept | Faham J | ||
| Nov 6, 2020 at 5:06 | vote | accept | Faham J | ||
| Nov 6, 2020 at 5:06 | |||||
| Nov 5, 2020 at 23:39 | history | edited | BioPhysicist | CC BY-SA 4.0 |
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| Nov 5, 2020 at 23:30 | answer | added | Mark H | timeline score: 4 | |
| Nov 5, 2020 at 23:21 | comment | added | nasu | The work done by a force does not depend on what you consider to be your system. And anyway the idea that the work of internal forces is zero is wrong. Forget about it. | |
| Nov 5, 2020 at 19:11 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 6 characters in body; edited tags; edited title; edited tags
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| Nov 5, 2020 at 19:10 | comment | added | Faham J | @nasu I related this "making a system" Concept to the pully block system... Where we used to concider some blocks as a system and the work done by tension becomes 0 as it became internal force... I was confused by that, that if there tension became internal force if we considered some blocks as system then why not here we can assign the two charges as a system and finalize the electrostatic work done as 0 as it's internal.. | |
| Nov 5, 2020 at 19:08 | comment | added | nasu | The work is not zero for your system. For each force the displacement is in the direction of the force so you add two positive contributions. | |
| Nov 5, 2020 at 19:04 | answer | added | R.W. Bird | timeline score: 1 | |
| Nov 5, 2020 at 18:55 | comment | added | The Photon | Consider an explosive device. No external force is applied to it, but when it goes off the kinetic energy of its parts increases dramatically. | |
| Nov 5, 2020 at 18:45 | history | asked | Faham J | CC BY-SA 4.0 |