Timeline for Probability of Finding a Quantum System in a Specific State
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 6, 2020 at 14:44 | comment | added | TheAkashain | Perfect, thank you so much! I marked your answer as correct and gave it an upvote (though that won't appear until my score is higher)! | |
| Oct 6, 2020 at 14:43 | comment | added | Charlie | Yes, note that even when $t\neq 0$ we have $|e^{-iEt/\hbar}|^2=1$ so it can be ignored for all $t$. | |
| Oct 6, 2020 at 14:42 | comment | added | TheAkashain | Okay it all just 'clicked' for me after seeing your comment. While my work may be wrong: $$|\frac{1}{\sqrt{6}} \cdot e^{-iEt/\hbar}|^2 = \frac{1}{6} \cdot |e^{-iE(0)/\hbar}|^2$$ Which should simplify to $\frac{1}{6}$ since it is a stationary state | |
| Oct 6, 2020 at 14:36 | vote | accept | TheAkashain | ||
| Oct 6, 2020 at 14:35 | comment | added | Charlie | What do you get when you calculate $\bigl| \frac{1}{\sqrt 6}\cdot e^{-iEt/\hbar} \bigr|^2$? That is the coefficient of $|\phi_3\rangle$. | |
| Oct 6, 2020 at 14:32 | comment | added | TheAkashain | So I got the state of the system equation at any time t (it was part B of the question) down to $$ \left(\frac{1}{\sqrt{3}} |\phi_1\rangle+ \frac{1}{\sqrt{2}} |\phi_2\rangle+ \frac{1}{\sqrt{6}} |\phi_3\rangle\right) e^{(-iEt/\hbar)},$$ though I'm not sure where to go from here for calculating probability | |
| Oct 6, 2020 at 14:29 | history | answered | Charlie | CC BY-SA 4.0 |