Timeline for What is the general solution of the Associated Legendre differential equation when $A$ does not equal $\ell(\ell+1)$?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Sep 29, 2020 at 21:38 | comment | added | Kristian Stokkereit | Will do, thanks again. | |
| Sep 29, 2020 at 21:19 | comment | added | G. Smith | I don’t have a proof and after searching for a few minutes I couldn’t find one. You could try asking on Math SE. | |
| Sep 29, 2020 at 20:56 | comment | added | Kristian Stokkereit | Also, do you have a proof that they cannot be normalised or can you recommend any sites/books that have a detailed proof available? Thanks again. | |
| Sep 29, 2020 at 19:58 | comment | added | Kristian Stokkereit | That helps a lot, thank you! | |
| Sep 29, 2020 at 19:19 | comment | added | G. Smith | If you don’t take $A=0,2,6,12,\dots$, then the solutions aren’t normalizable. This is where the quantization comes from. So you understood it correctly. | |
| Sep 29, 2020 at 18:00 | comment | added | Kristian Stokkereit | Okay, I was under the impression that the eigenstates had angular momentum quantisation because of this point that only the angular momentum eigenstates converge correctly so that quantises the angular momentum operator on this state, but have I got it the wrong way around? the the constant A is set equal to l(l+1) to make it an eigenstate of the total angular momentum operator and the form yields the associated legendre differential equation? Again sorry for lack of clarity and thank you for your help. | |
| Sep 29, 2020 at 17:42 | history | edited | G. Smith | CC BY-SA 4.0 |
added 393 characters in body
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| Sep 29, 2020 at 17:31 | history | answered | G. Smith | CC BY-SA 4.0 |