Timeline for Product used in equations of motion [closed]
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Sep 17, 2020 at 11:52 | vote | accept | Shreyansh Kuntal | ||
| Sep 16, 2020 at 8:26 | history | closed |
ZeroTheHero Cosmas Zachos GiorgioP-DoomsdayClockIsAt-90 Jon Custer Voulkos |
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| Sep 15, 2020 at 14:48 | comment | added | Cosmas Zachos | Division by a dot product, $\vec a \cdot \vec a$ is allowed, if this quantity is non-vanishing, so dotting the first equation by $\vec a$ gets you there. | |
| Sep 15, 2020 at 13:32 | review | Close votes | |||
| Sep 16, 2020 at 8:27 | |||||
| Sep 15, 2020 at 13:20 | history | edited | Qmechanic♦ |
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| Sep 15, 2020 at 13:15 | answer | added | gandalf61 | timeline score: 1 | |
| Sep 15, 2020 at 9:42 | comment | added | Rob | My guess would be that the implied vector product is the dot product, which can be used to express the magnitude of a vector $||\vec v||^2 = \vec v \cdot \vec v$. For your second question, if all the vectors are known but time is not, you can simply restrict to looking at one coordinate/one dimension of the problem and solve for t there. The equation is quadratic so there are at most two solutions, and if you need to distinguish which of the two is the right answer (if the answer is nontrivial), you can solve the same equation in the second coordinate, and compare the two solutions for t | |
| Sep 15, 2020 at 9:37 | history | asked | Shreyansh Kuntal | CC BY-SA 4.0 |