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S Sep 24, 2020 at 18:04 history bounty ended CommunityBot
S Sep 24, 2020 at 18:04 history notice removed CommunityBot
Sep 19, 2020 at 6:21 comment added Pipe Here you can find the answer.
Sep 17, 2020 at 7:23 comment added Roger V. @Buzz you mean relativistic QFT. In condensed matter QFT operators can be defined differently - depending on how one describes holes. I suppose this is the key to the question: what is meant by "vacuum"?
Sep 16, 2020 at 17:08 comment added Buzz @Vadim The question’s notation is standard. Field operators in quantum field theory are a mixture of annihilation operators for particles and creation operators for antiparticles.
Sep 16, 2020 at 16:58 comment added Roger V. If you mean by "vacuum" the vacuum state, then it must be destroyed by an annihilation operator. If $\Psi$ is a creation operator, then $\Psi^\dagger$ is a better notation.
S Sep 16, 2020 at 16:51 history bounty started Solidification
S Sep 16, 2020 at 16:51 history notice added Solidification Canonical answer required
Sep 14, 2020 at 12:28 history asked Solidification CC BY-SA 4.0