Timeline for What is the geometric derivation of 2D Fraunhofer aperture diffraction?
Current License: CC BY-SA 4.0
3 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Dec 26, 2022 at 3:50 | comment | added | Thomas | @AlexGower Did you ever figure this out? I've run into this exact problem as well, all the derivations I have seen are 1D and I understand perfectly well that it works in 1D, but when considering off-axis points in 2D my attempts show that the path length differences across the aperture start having terms of the form $\sqrt{x^2 +y^2}$ (coefficients omitted) which makes the subsequent integrals intractable. Am I missing something obvious or is this just being handwaved away? | |
Aug 27, 2020 at 8:50 | comment | added | Alex Gower | Even with this approximation, I'm not sure how the total path length difference can just be equal to the path length difference in the x direction + the path length difference in the y direction. Its obvious geometrically for the 1D case, but I've not seen a geometrical diagram to show it for 2D. | |
Aug 26, 2020 at 12:37 | history | answered | mike stone | CC BY-SA 4.0 |