Timeline for Does Relativity make a difference on whether Earth revolves around the Sun or not?
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 21, 2020 at 7:50 | comment | added | Vaibhav Pankhala | now i will first read full GR only then i will reply or come to this question | |
| Aug 21, 2020 at 6:07 | history | edited | Agnius Vasiliauskas | CC BY-SA 4.0 |
deleted 13 characters in body
|
| Aug 20, 2020 at 16:50 | comment | added | Agnius Vasiliauskas | Start on Separating non-inertial from inertial reference frames. Then you can think yourself an experiments designed to discover inertial forces. For example, suppose you push accelerator in a car which moves towards another car at rest. You may think that another is identical and can be interpreted also pushing accelerator towards you. NO. Only your car passengers will experience inertial force which leans you towards seats ! Thus you can say which car moves with acceleration. | |
| Aug 20, 2020 at 16:21 | comment | added | Vaibhav Pankhala | sir ,i was just asking rational questions sir as per my attitude.but can you please provide link of those experiments because i am unable to find it.kindly help me. | |
| Aug 20, 2020 at 16:14 | comment | added | Agnius Vasiliauskas | @VaibhavPankhala i think you are starting to nag and gobble. I think you've got the main idea of difference between inequality of reference frames so we can end this discussion. Btw, what i said is nothing new. That local experiments helps to identify non-inertial reference frame was known before, just Google it. | |
| Aug 20, 2020 at 16:08 | comment | added | Vaibhav Pankhala | actually you first said on sun will not detect gravity variations. i don't think this can be measured by thought experiment. :) | |
| Aug 20, 2020 at 16:04 | comment | added | Agnius Vasiliauskas | @VaibhavPankhala it doesn't matter if somebody does or doesn't. It's a thought experiment how to distinguish inertial reference frame from non-inertial one. The fact that you can or can't perform measurements somewhere doesn't changes principle why those frames are not identical. | |
| Aug 20, 2020 at 15:58 | comment | added | Vaibhav Pankhala | have anyone gone on sun to detect those variations?? | |
| Aug 20, 2020 at 15:57 | comment | added | Agnius Vasiliauskas | @VaibhavPankhala No, you can't. On sun you will not detect gravity variations due to "supposed rotation around earth". I. E. In short, you can detect acceleration by performing local experiments on reference frame. On sun you will not detect it, on earth - you will. Thus those RF are not identical. Just follow my arguments. | |
| Aug 20, 2020 at 15:42 | comment | added | Vaibhav Pankhala | What do you mean by earth is rotating around us? actually earth is rotating on its own axis and its surface is facing sun that's why we say its rotating around sun. now sun is also rotating around its own axis. en.wikipedia.org/wiki/Solar_rotation see this. so can't we follow this argument to show that sun is rotating around earth | |
| Aug 20, 2020 at 15:29 | comment | added | Agnius Vasiliauskas | @VaibhavPankhala you don't understood. Sun is not rotating around us, thus it will not have centrifugal acceleration, like we do. Not the calculation is problem. On sun surface you will not measure gravity variations due to centrifugal acceleration around "earth to be". But you will measure it on Earth. Thus those reference frames are not identical. | |
| Aug 20, 2020 at 15:15 | comment | added | Vaibhav Pankhala | i don't see how this depicts it why can't we calculate this term. we know R and sun's rotation is too happening on its axis. | |
| Aug 20, 2020 at 14:49 | comment | added | Agnius Vasiliauskas | @VaibhavPankhala yes, exactly. It's our centrifugal acceleration due to orbiting the Sun. | |
| Aug 20, 2020 at 14:21 | comment | added | Vaibhav Pankhala | you mean this third term v^s/R | |
| Aug 20, 2020 at 13:57 | history | answered | Agnius Vasiliauskas | CC BY-SA 4.0 |