Timeline for Place each foot on a scale: can you add the two to find your weight?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| May 30, 2015 at 6:13 | history | protected | Qmechanic♦ | ||
| Mar 18, 2013 at 19:30 | comment | added | Nathan Reed | @toon81 No; friction could hold the scales in place against the horizontal component of the force. | |
| Mar 18, 2013 at 17:52 | comment | added | toon81 | So basically what you're saying is, that if I "did a split", then there is a significant component of my weight that points perpendicular to the normal of the scale's surface, that isn't being measured; but if that's the case, wouldn't that make the scale move horizontally? Doesn't the fact that the scales stand still (assuming they do) imply that no such components exists? | |
| Mar 18, 2013 at 17:48 | vote | accept | toon81 | ||
| Mar 18, 2013 at 17:47 | comment | added | Dan Piponi | Yes but for one source of error. If you stand on a pair of scales, the force on each may have equal (but opposite) horizontal forces. This will likely mess up the reading for some designs of scale where the assumption was that the force would be vertical. | |
| Mar 18, 2013 at 17:25 | answer | added | joshphysics | timeline score: 6 | |
| Mar 18, 2013 at 16:30 | answer | added | Moving Massive | timeline score: 2 | |
| Mar 18, 2013 at 16:29 | history | edited | toon81 | CC BY-SA 3.0 |
title is now slightly clearer.
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| Mar 18, 2013 at 16:14 | review | First posts | |||
| Mar 18, 2013 at 16:18 | |||||
| Mar 18, 2013 at 15:59 | history | asked | toon81 | CC BY-SA 3.0 |