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Aug 1, 2020 at 10:42 comment added Vercassivelaunos Counterexample: take any two states with same quantum number $n$ but different quantum number $l$. Their linear combination will still be an energy eigenstate , but not an angular momentum eigenstate.
Aug 1, 2020 at 10:39 comment added DoeJohn "all eigenfunctions must be simultaneously eigenfunctions of angular momentum". This is incorrect. They do not are necessarily simultaneous eigenfunctions. Rather, there exists a basis of such simultaneous eigenfunctions, which is particularly convenient. But that is not the only possible basis made of energy eigenstates.
Aug 1, 2020 at 10:06 history answered my2cts CC BY-SA 4.0