Timeline for When studying the hydrogen atom, why do we seek simultaneous eigenfunctions of $\hat{L}^2$, $\hat{L}_z$, and $\hat{H}$?
Current License: CC BY-SA 4.0
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Aug 1, 2020 at 13:21 | vote | accept | Mr. Palomar | ||
Aug 1, 2020 at 10:35 | answer | added | Vercassivelaunos | timeline score: 3 | |
Aug 1, 2020 at 10:12 | comment | added | Mr. Palomar | Thanks @Vercassivelaunos. I was under the impression that this would only be true when considering eigenvalues of a single operator, but it seems that I am mistaken. | |
Aug 1, 2020 at 10:10 | answer | added | Philip | timeline score: 1 | |
Aug 1, 2020 at 10:08 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
deleted 88 characters in body
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Aug 1, 2020 at 10:08 | comment | added | Vercassivelaunos | The physical state of a hydrogen atom doesn't have to be an eigenstate of all these operators. But it can always be written as a linear combination of those eigenstates. In quantum mechanics, we're always looking for a basis of the Hilbert space which makes calculations convenient. The set of eigenstates of the given operators is such a convenient basis. But there's nothing preventing you from finding an atom in a state which is not one of those eigenstates. It will simply take more symbols to write it down, for instance $\frac{1}{\sqrt2}(\vert n=1\rangle+\vert n=2\rangle)$. | |
Aug 1, 2020 at 10:07 | history | edited | Qmechanic♦ |
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Aug 1, 2020 at 10:06 | answer | added | my2cts | timeline score: -2 | |
Aug 1, 2020 at 9:54 | answer | added | FGSUZ | timeline score: 1 | |
Aug 1, 2020 at 9:43 | answer | added | Leiba Goldstein | timeline score: 0 | |
S Aug 1, 2020 at 9:39 | history | suggested | A. Bordg | CC BY-SA 4.0 |
fixed formatting in title + spelling
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Aug 1, 2020 at 9:38 | review | Suggested edits | |||
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Aug 1, 2020 at 9:25 | review | First posts | |||
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Aug 1, 2020 at 9:22 | history | asked | Mr. Palomar | CC BY-SA 4.0 |