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S Aug 4, 2020 at 3:41 history bounty ended The Pointer
S Aug 4, 2020 at 3:41 history notice removed The Pointer
Aug 4, 2020 at 3:41 vote accept The Pointer
Aug 4, 2020 at 3:41 vote accept The Pointer
Aug 4, 2020 at 3:41
Aug 4, 2020 at 2:04 answer added atarasenko timeline score: 0
Aug 4, 2020 at 0:57 comment added The Pointer @atarasenko Oh wow, I think you're right. Thank you for that. Looking through that Wikipedia article, I think I was on the right track with $\nabla \left[ \left( \rho \dfrac{\partial{\epsilon}}{\partial{\rho}} \right)_T \dfrac{\langle \mathbf{E}^2 \rangle}{8 \pi} \right] = \nabla \left[ \left( \rho \dfrac{\partial{n^2}}{\partial{\rho}} \right)_T \dfrac{I}{4 \pi c n \epsilon_0} \right]$! But which formula in particular should I be using? The closest that I can see might be $\mu _{0}\varepsilon _{0} = 1/c^{2}$, but this still doesn't get us what we need. Do you know enough to post an answer?
Aug 4, 2020 at 0:37 comment added atarasenko The formula you are trying to prove is written in gaussian units (en.wikipedia.org/wiki/Gaussian_units), and equations that contain $\epsilon_0$ and $\mu_0$ are written in SI units.
Aug 3, 2020 at 9:00 history tweeted twitter.com/StackPhysics/status/1290210816751480832
S Jul 31, 2020 at 3:43 history bounty started The Pointer
S Jul 31, 2020 at 3:43 history notice added The Pointer Draw attention
Jul 28, 2020 at 18:15 history edited The Pointer CC BY-SA 4.0
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Jul 28, 2020 at 18:08 history asked The Pointer CC BY-SA 4.0