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Jul 24, 2020 at 4:40 comment added jcai Just to add to this, I verified (manually in the Weyl basis) that $\not p - m$ becomes singular as a spinor matrix when $m = \sqrt{\not p^2}$, justifying the assertion that $\not p = m_P$ is a pole.
Jul 24, 2020 at 4:37 vote accept jcai
Jul 24, 2020 at 2:42 history answered Technically Natural CC BY-SA 4.0