Timeline for Relationship between classical $q$-deformed General Relativity and the cosmological constant

8 events

when toggle format	what		by	license	comment
Jul 14, 2020 at 13:49	comment	added	MadMax		@Prof.Legolasov, actually it's adding the non-commuting $e^K$ (rather than $\varepsilon_{IJKL} e^K \wedge e^L$) to $\omega_{IJ}$, since the q-deformed connection is required to be a 1-form ( $\varepsilon_{IJKL} e^K \wedge e^L$ is 2-form). You can rewrite the q-deformed connection $\omega^I_{\;J} + qe^K=\omega^I_{\;J} + qe^K_{\;4} = \omega^a_{q\;b}$, with $a,b = 0, 1, 2, 3, 4$.
Jul 14, 2020 at 10:41	vote	accept	Prof. Legolasov
Jul 14, 2020 at 2:25	comment	added	Prof. Legolasov		I think I understand the intuition. $\varepsilon_{IJKL} e^K \wedge e^L$ is canonically conjugate to $\omega_{IJ}$, so it doesn’t commute with it and adding it to $\omega$ will make it a quantum group connection. Is that what you meant?
Jul 13, 2020 at 19:43	history	edited	MadMax	CC BY-SA 4.0	added 84 characters in body
Jul 13, 2020 at 18:56	comment	added	MadMax		The dS (q-deformed Lorentz) connection has two parts $\omega^I_{\;J} + q e^I$.
Jul 13, 2020 at 18:49	comment	added	Prof. Legolasov		Nice! How does $e$ make it into the $q$-deformed curvature though?
Jul 13, 2020 at 17:37	history	edited	MadMax	CC BY-SA 4.0	deleted 2 characters in body
Jul 13, 2020 at 17:30	history	answered	MadMax	CC BY-SA 4.0