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Jul 10, 2020 at 17:09 comment added Prof. Legolasov @user56834 $d$ is the exterior derivative which for scalar functions like $H$ is just the gradient, and $i_v$ is the contraction operator parameterized by a vector field $v$. If you are familiar with tensors and index notation, $(dH)_a = \partial H / \partial x^a$, and $(i_v \omega)_a = v^b \omega_{ab}$.
Jul 10, 2020 at 14:10 comment added user56834 Thank you. I actually don't understand either of these equations (I just asked a question about symplectic geometry here: physics.stackexchange.com/q/564834). What is $i_{V_H}\omega$, or $dH$?
Jul 10, 2020 at 13:51 history answered spiridon_the_sun_rotator CC BY-SA 4.0