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Jul 14, 2020 at 20:28 comment added Codebling Awesome, thanks!!
Jul 14, 2020 at 16:49 comment added Kayla Kornoelje It is out of "Conquering the Physics GRE" as roshoka had claimed!
Jul 13, 2020 at 23:27 comment added Codebling What textbook is this from? I like the explanation
Jul 5, 2020 at 18:16 vote accept Kayla Kornoelje
Jul 3, 2020 at 16:41 answer added roshoka timeline score: 1
Jul 3, 2020 at 16:20 answer added JamalS timeline score: 0
Jul 3, 2020 at 15:30 history edited Qmechanic CC BY-SA 4.0
deleted 1 character in body; edited tags; edited title
Jul 3, 2020 at 15:26 answer added Charlie timeline score: 0
Jul 3, 2020 at 15:15 comment added ɪdɪət strəʊlə It might help to notice that if $A$ is an operator, then $A|n\rangle$ is a new state $|m\rangle$. So $\langle k | A | n \rangle = \langle k | m \rangle $. Choosing $\langle k| = \langle 3|$, $|n\rangle = |3\rangle$ and $A = (a+a^\dagger)^2$ is exactly the problem in the picture.
Jul 3, 2020 at 15:12 review First posts
Jul 3, 2020 at 16:11
Jul 3, 2020 at 15:07 history asked Kayla Kornoelje CC BY-SA 4.0