Timeline for What's the actual path of the planets?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 3, 2020 at 11:58 | comment | added | Vamsi Krishna | @Heterotic Thanks but I wanted to visualise it from a frame within our solar system, | |
| Jul 2, 2020 at 9:25 | comment | added | Heterotic | helpful(?) visualization: reddit.com/r/physicsgifs/comments/awba5b/… | |
| Jul 2, 2020 at 3:25 | comment | added | anna v | @VamsiKrishna if you want to get the mathematics at that reference frame, you can be thinking of a different ellipse. It is a moving ellipse map | |
| Jul 1, 2020 at 15:59 | comment | added | Vamsi Krishna | @annav I thought about it as, at any particular instant in a planet's path it tends to revolve in an elliptical orbit. That's the instantaneous path. But as the focus moves too, the orbit shifts to a different ellipse. Is it a right way to think about it? | |
| Jul 1, 2020 at 15:10 | comment | added | anna v | @GiorgioP I am trying to give the analogy that the mathematical map is always there when in the correct reference frame, and will be there in a much more complicated way if the reference frame is moving. Think of describing the shape of the basket ball while in motion. It is always very easy to get complicated mathematical relationships out of simple ones by changing frames of reference.. | |
| Jul 1, 2020 at 13:41 | comment | added | GiorgioP-DoomsdayClockIsAt-90 | In the previous example it is the distance between a point of the trajectory and the origin, in the first case, and a point of the trajectory and the point of coordinates $(vt,0)$, in the second. | |
| Jul 1, 2020 at 13:40 | comment | added | GiorgioP-DoomsdayClockIsAt-90 | By elliptic mapping you are describing an implici change of reference. However, there i no way, orbits are not frame-invanriant. Take a circular orbit. It can be described by the parametric equation $x=R cos( \omega t) ; y = R sin( \omega t)$ in one frame. In a uniformly translating frame the equations could be $x=v t + R cos( \omega t) ; y = R sin( \omega t)$. The first curve is closed and not self-intersecting. The second one is open and self-intersecting. Therefore the shape of the orbit is frame-dependent. This does not exclude that some invariand relation beteween ponts could exist. | |
| Jul 1, 2020 at 12:38 | history | answered | anna v | CC BY-SA 4.0 |