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Jun 29, 2020 at 6:11 comment added Gert You are correct and I'm wrong. I edited my answer. Thank you for pointing out my error. +1 from me.
Jun 28, 2020 at 17:40 comment added Gert The law of energy conservation is certainly valid if you take all energies into account. Which you don't do!
Jun 28, 2020 at 17:37 comment added atarasenko The law of energy conservation is still valid: the work done to permanently deform the cup changes its energy and is partially turned into heat. See the first law of thermodynamics
Jun 28, 2020 at 16:55 comment added Gert And your (dismissed) energy balance doesn't take into account the work done to permanently deform the cup, as witnessed by me.
Jun 28, 2020 at 16:09 comment added Gert In the 'final analysis' I don't think it matters much: we're not here to create a precise model, although it would be possible to refine what we have and empirically verify it.
Jun 28, 2020 at 16:07 comment added Gert My derivation starts from the idea the collision is INELASTIC, so kinetic and potential energy are NOT conserved. Hence the use of conservation of momentum. Your $E_{cup}=E_{water}=E_{heat}=0$ argument just makes me giggle!
Jun 28, 2020 at 16:04 history edited atarasenko CC BY-SA 4.0
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Jun 28, 2020 at 15:58 history answered atarasenko CC BY-SA 4.0