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Qmechanic ♦
Qmechanic ♦
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In a simple pendulum, what is the tension in string either T= mgcos@$T= mg\cos\alpha$ or T=$T= mg/cos@\cos\alpha$?

In a simple pendulum, $\alpha$ is angle between string and vertical, $T$ is tension in string and $mg$ be pull on the bob.
$T$ has 2 component $T\cos\alpha$ and $T\sin\alpha$ $mg$ has 2 components $mg\sin\alpha$ and $mg\cos\alpha$. I get that $mg\cos\alpha=T$ and $mg=T\cos\alpha$. So I got 2 values of tension at a same time $mg\cos\alpha$ and $mg/\cos\alpha$. I could not figure out the value of tension.

Thanks in advance

In a simple pendulum, what is the tension in string either T= mgcos@ or T= mg/cos@

In a simple pendulum, $\alpha$ is angle between string and vertical, $T$ is tension in string and $mg$ be pull on the bob.
$T$ has 2 component $T\cos\alpha$ and $T\sin\alpha$ $mg$ has 2 components $mg\sin\alpha$ and $mg\cos\alpha$. I get that $mg\cos\alpha=T$ and $mg=T\cos\alpha$. So I got 2 values of tension at a same time $mg\cos\alpha$ and $mg/\cos\alpha$. I could not figure out the value of tension.

Thanks in advance

In a simple pendulum, what is the tension in string either $T= mg\cos\alpha$ or $T= mg/\cos\alpha$?

In a simple pendulum, $\alpha$ is angle between string and vertical, $T$ is tension in string and $mg$ be pull on the bob.
$T$ has 2 component $T\cos\alpha$ and $T\sin\alpha$ $mg$ has 2 components $mg\sin\alpha$ and $mg\cos\alpha$. I get that $mg\cos\alpha=T$ and $mg=T\cos\alpha$. So I got 2 values of tension at a same time $mg\cos\alpha$ and $mg/\cos\alpha$. I could not figure out the value of tension.

Changed "@" by angle "alpha"
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BioPhysicist
BioPhysicist
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Changed "@" by angle "alpha"
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edit approved Jun 18, 2020 at 15:06
ProfM
edit approved Jun 18, 2020 at 15:06
ProfM
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In a simple pendulum, @$\alpha$ is angle between string and vertical, T$T$ is tension in string and mg$mg$ be pull on the bob.
T$T$ has 2 component Tcos@$T\cos\alpha$ and Tsin@$T\sin\alpha$ mg$mg$ has 2 components mg sin@$mg\sin\alpha$ and mgcos@$mg\cos\alpha$. I get that mgcos@=T$mg\cos\alpha=T$ and mg=Tcos@ $mg=T\cos\alpha$. So I got 2 values of yensiontension at a same time mgcos@$mg\cos\alpha$ and mg/cos@$mg/\cos\alpha$. I couldnotcould not figure out the value of tension.

Thanks in advance

In a simple pendulum, @ is angle between string and vertical, T is tension in string and mg be pull on the bob.
T has 2 component Tcos@ and Tsin@ mg has 2 components mg sin@ and mgcos@. I get that mgcos@=T and mg=Tcos@. So I got 2 values of yension at a same time mgcos@ and mg/cos@. I couldnot figure out the value of tension.

Thanks in advance

In a simple pendulum, $\alpha$ is angle between string and vertical, $T$ is tension in string and $mg$ be pull on the bob.
$T$ has 2 component $T\cos\alpha$ and $T\sin\alpha$ $mg$ has 2 components $mg\sin\alpha$ and $mg\cos\alpha$. I get that $mg\cos\alpha=T$ and $mg=T\cos\alpha$. So I got 2 values of tension at a same time $mg\cos\alpha$ and $mg/\cos\alpha$. I could not figure out the value of tension.

Thanks in advance

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Tom Curran
Tom Curran
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