Timeline for Relation of speeds of Earth at extremities of orbit through force
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Jun 6, 2020 at 21:59 | history | edited | Qmechanic♦ |
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| Jun 6, 2020 at 20:54 | comment | added | TheChemist | I know this is not a viable source but I just wanted to confirm that the first answer by "Gio" is indeed wrong @bill | |
| Jun 6, 2020 at 20:46 | answer | added | TheChemist | timeline score: 0 | |
| Jun 6, 2020 at 20:42 | comment | added | TheChemist | Oh ok , thanks a lot. | |
| Jun 6, 2020 at 20:41 | comment | added | Bill Watts | Very elementary books maybe. For elliptic motion you have a radial component as well as a tangential component for velocity except at the extremities. | |
| Jun 6, 2020 at 20:38 | comment | added | TheChemist | Ok so basically most books , in order to make calculations easier assume the orbit to be circular and hence we are able to appy the circular motion formula , right? | |
| Jun 6, 2020 at 20:37 | comment | added | Bill Watts | The general 2 body problem is more complicated and a separate question. But no, we do not use the circular motion formula for elliptic motion. | |
| Jun 6, 2020 at 20:32 | comment | added | TheChemist | But , don't we calculate the values of speeds at different points in an elliptical orbit using $F=m/v^2/r$ and if not then how do we calculate speeds at these different points ?@Bill | |
| Jun 6, 2020 at 20:30 | comment | added | Bill Watts | $F = m\ v^2/r$ is only valid for circular motion. | |
| Jun 6, 2020 at 20:30 | history | edited | TheChemist | CC BY-SA 4.0 |
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| Jun 6, 2020 at 20:27 | review | First posts | |||
| Jun 6, 2020 at 20:29 | |||||
| Jun 6, 2020 at 20:22 | history | asked | TheChemist | CC BY-SA 4.0 |