Timeline for Are all vector-bosons gauge-bosons?
Current License: CC BY-SA 4.0
12 events
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May 27, 2020 at 23:33 | comment | added | fewfew4 | It's absolutely worth an answer though! | |
May 27, 2020 at 19:46 | comment | added | Ramiro Hum-Sah | I agree, tparker's answer and yours are both excellent and much more appropriate that the one of mine :) Examples from KK-like theories or string theories are exotic (exactly because the need of an infinite tower of massive states) and out of place. Thanks for your answer and comments. | |
May 27, 2020 at 18:38 | comment | added | fewfew4 | Thought I should comment that while this is possible, it necessarily requires an infinite tower of mass excitations. This might be unsavory for OP. | |
May 26, 2020 at 16:15 | comment | added | Ramiro Hum-Sah | I am sorry, I complicated the answer so much, that was not my intention :( I hope that the answer must still be useful. | |
May 26, 2020 at 16:14 | comment | added | Davide Morgante | @RamiroHum-Sah Yeah, i feel like string theory for now over my competences! Very cool though, thanks for the thorough explanation. | |
May 26, 2020 at 16:08 | comment | added | Ramiro Hum-Sah | Then, KR vectors are $U(1)$ gauge vectors with (local and unitary interactions) with extra higher derivative corrections (self-interactions and other coupling to other fields) suppressed by extra parameters that are not the gauge coupling. Then Maor is right, extra fields are required for consistency. | |
May 26, 2020 at 16:06 | comment | added | Ramiro Hum-Sah | Just to try to be clear: KR vector bosons are gauge bosons except for a detail. Higher polynomials in the YM 4-potential can not be added to the Yang-Mills lagrangian without violating the rule of minimal coupling and renormalizability, the same is true for the KR fields; except that in string theory there is other parameter (the string lenght) and KR fields can be "corrected" by higher polynomials in $B_{\mu \nu}$ without destroying unitarity and renormalizability. | |
May 26, 2020 at 15:50 | comment | added | Ramiro Hum-Sah | Physically: If you explore the behaviour of the effective Kalb-Ramond vector fields $B_{\mu i}$ at strong coupling, you should discover that they should start to behave as the components of a single multiplet is higher dimensions $B_{\mu \nu}$. Something not expected for gauge bosons. | |
May 26, 2020 at 15:49 | comment | added | Ramiro Hum-Sah | Dear Davide: No, it cannot be a gauge boson. Mathematically: $B_{\mu i}$ is not a connection on any principal bundle, is the component of a higher gauge field. Even if you restrict $B_{\mu \nu}$ to $B_{\mu i}$ you can not obtain nothing isomorphic to a gauge bundle because the deformation theories are not equal. | |
May 26, 2020 at 15:36 | comment | added | myorbs | In that answer it seems to be assumed that the vectors are gauge bosons, for some reason. Also I wonder if it is neccesary to include extra fields (graviton and scalar) to get the theory to be consistent? I may be asking a silly question since I am not very familiar with string theory | |
May 26, 2020 at 15:26 | comment | added | Davide Morgante | Interestingly enough, if i'm not mistaken, in the link you gave the Kalab-Ramond field is indicated as a gauge boson. | |
May 26, 2020 at 15:15 | history | answered | Ramiro Hum-Sah | CC BY-SA 4.0 |