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May 25, 2020 at 14:13 comment added Bastam Tajik Also by imposing gauge invariance on the four point function of the new interactive term, the coupling should be the same!
May 25, 2020 at 14:04 comment added Bastam Tajik Well first of all, we're to all extent still within the paradigm of Yang-Mills theory and gauge invariance is the golden rule. I was considering to write down a new gauge invariant interaction term between the two sectors. And it's nothing but the renormalizable operator of the trace of the multiplication of the two W bosons field strengths. $Tr(F_{1}*F_{2})$ Idk if this term can modify the perturbation theory significantly or not.
May 25, 2020 at 0:00 comment added Prof. Legolasov @BastamTajik in your construction, the two $SU(2)$ from a Cartesian product group. The corresponding Lie algebra generators commute with each other. Therefore, a Yang-Mills theory built around your gauge groups will have the two $W/Z$ bosons which don’t interact with each other. You could always try writing down something other than Yang-Mills, but I’m not aware of any such successful approach.
May 24, 2020 at 23:57 comment added Bastam Tajik And even if I include an inner product of the two W fields in the lagrangian to add a vertex for the W particle to change the first W to the second one, it seems that I lose gauge invariance explicitly. True?
May 24, 2020 at 23:52 vote accept Bastam Tajik
May 24, 2020 at 20:33 history answered Prof. Legolasov CC BY-SA 4.0