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May 21, 2020 at 14:39 comment added M. Enns It still sounds like you are trying to compare apples and oranges. Let's do a rough calculation. Say you had a 60 W incandescent bulb ~5% efficient so 3 W of light energy. Let's pick yellow light in the middle of the visible spectrum so f=5x10^14 Hz. The energy of one photon is given by E=hf = 6.6x10^-34 x 5x10^14 = 3.3x10^-19 J. Dividing 3 J/s by the energy per photon gives 9x10^18 photons per second. So this number is more than the frequency of a single UV photon but it all depended on what power of bulb we decided to start with.
May 21, 2020 at 13:03 comment added PDD OK. Thank you for your answer. Can I say that bright light source had frequency more than ultraviolet light (per second) because of cumulative frequency overlay? (exclude even all non visible spectrum from which is white light too)
May 19, 2020 at 16:04 history answered M. Enns CC BY-SA 4.0