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Feb 28, 2013 at 1:18 comment added Shivam Sarodia With electron current, we actually do not obtain the same result as before for the voltage in the branch containing Y since decreasing the resistance of one of the resistors increased the current in that branch. Since the resistor was changed to 15 ohms, the voltage drop in electron current is $60/(15+60) = 0.8$ times the original 12 V, which is 9.6 V, leaving 2.4 V at node Y. Using a similar process to find the voltages at node X and Y for both electron and conventional current finds that the voltage difference is consistently 5.6 V in this new circuit.
Feb 27, 2013 at 17:05 comment added ithisa What if I change the 30 ohm resistor to the left of Y to 15 ohms? Now if we solve with the conventional current, we will obtain a different result (the Y would encounter a 15 ohm rather than a 30 ohm). With electron current, we obtain the same result as the previous one, as the first resistor encountered is a 30 ohm on the top, and the first resistor encountered is a 60 ohm on the bottom. Isn't this a contradiction?
Feb 27, 2013 at 14:48 history answered Shivam Sarodia CC BY-SA 3.0