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Suppose that you have a neutral plate whose potential relative to the "ground" is zero.

As photo-electrons are emitted from the plate, the potential of the plate increases, and so subsequent photo-electrons are attracted to the plate but if they have sufficient kinetic energy they will escape from the plate.

However, there will come a time when the potential of the plate, $V_{\rm plate}$, is such that the photo-electrons have a maximum kinetic energy, $K_{\rm max}$, which is insufficient for them to escape from the plate, $eV_{\rm plate} > K_{\rm max}$.

So after escaping the photo-electrons will be "dragged" back to the plate.

So the photoelectrons will suffer negative acceleration of magnitude $eE$ where $E$ id the magnitude of the electric field and equal to the potential gradient.

Suppose that you have a neutral plate whose potential relative to the "ground" is zero.

As photo-electrons are emitted from the plate, the potential of the plate increases, and so subsequent photo-electrons are attracted to the plate but if they have sufficient kinetic energy they will escape from the plate.

However, there will come a time when the potential of the plate, $V_{\rm plate}$, is such that the photo-electrons have a maximum kinetic energy, $K_{\rm max}$, which is insufficient for them to escape from the plate, $eV_{\rm plate} > K_{\rm max}$.

So after escaping the photo-electrons will be "dragged" back to the plate.

Suppose that you have a neutral plate whose potential relative to the "ground" is zero.

As photo-electrons are emitted from the plate, the potential of the plate increases, and so subsequent photo-electrons are attracted to the plate but if they have sufficient kinetic energy they will escape from the plate.

However, there will come a time when the potential of the plate, $V_{\rm plate}$, is such that the photo-electrons have a maximum kinetic energy, $K_{\rm max}$, which is insufficient for them to escape from the plate, $eV_{\rm plate} > K_{\rm max}$.

So after escaping the photo-electrons will be "dragged" back to the plate.

So the photoelectrons will suffer negative acceleration of magnitude $eE$ where $E$ id the magnitude of the electric field and equal to the potential gradient.

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Suppose that you have a neutral plate whose potential relative to the "ground" is zero.

As photo-electrons are emitted from the plate, the potential of the plate increases, and so subsequent photo-electrons are attracted to the plate but if they have sufficient kinetic energy they will escape from the plate.

However, there will come a time when the potential of the plate, $V_{\rm plate}$, is such that the photo-electrons have a maximum kinetic energy,K_{\rm max} $K_{\rm max}$,which which is insufficient to for them to escape from the plate, $eV_{\rm plate} > K_{\rm max}$.

So after escaping the photo-electrons will be "dragged" back to the plate.

Suppose that you have a neutral plate whose potential relative to the "ground" is zero.

As photo-electrons are emitted from the potential of the plate increases and so subsequent photo-electrons are attracted to the plate but if they have sufficient kinetic energy they will escape from the plate.

However, there will come a time when the potential of the plate, $V_{\rm plate}$, is such that the photo-electrons have a maximum kinetic energy,K_{\rm max} ,which is insufficient to for them to escape from the plate, $eV_{\rm plate} > K_{\rm max}$.

So after escaping the photo-electrons will be "dragged" back to the plate.

Suppose that you have a neutral plate whose potential relative to the "ground" is zero.

As photo-electrons are emitted from the plate, the potential of the plate increases, and so subsequent photo-electrons are attracted to the plate but if they have sufficient kinetic energy they will escape from the plate.

However, there will come a time when the potential of the plate, $V_{\rm plate}$, is such that the photo-electrons have a maximum kinetic energy, $K_{\rm max}$, which is insufficient for them to escape from the plate, $eV_{\rm plate} > K_{\rm max}$.

So after escaping the photo-electrons will be "dragged" back to the plate.

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Farcher
  • 99.9k
  • 5
  • 83
  • 215

Suppose that you have a neutral plate whose potential relative to the "ground" is zero.

As photo-electrons are emitted from the potential of the plate increases and so subsequent photo-electrons are attracted to the plate but if they have sufficient kinetic energy they will escape from the plate.

However, there will come a time when the potential of the plate, $V_{\rm plate}$, is such that the photo-electrons have a maximum kinetic energy,K_{\rm max} ,which is insufficient to for them to escape from the plate, $eV_{\rm plate} > K_{\rm max}$.

So after escaping the photo-electrons will be "dragged" back to the plate.