Timeline for Dispersion relation with damping force
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 12, 2020 at 19:34 | comment | added | Amateur Physicist | I reduced the problem to the nearest neighbors and I found $m\ddot{u}_n = Ku_{n-1} + Ku_{n+1} -2Ku_n -\Gamma\dot{u}_n$ where $u_n$ is the displacement for the nth atom in my chain. With the anstaz $\mathbf{u}_{n}=\frac{1}{\sqrt{m}} \mathbf{u}(q)e^{i( \mathbf{q}. \mathbf{r}_n -\omega t)}$. I think my derivation is correct, but maybe I have to consider $-\Gamma\dot{u}_{n-1}$ and $-\Gamma\dot{u}_{n-1}$. I did it and I just find a cosine in the imaginary part. | |
| May 12, 2020 at 19:19 | comment | added | Superfast Jellyfish | What’s the differential equation you’re considering? | |
| May 12, 2020 at 19:08 | comment | added | Amateur Physicist | By the way, do you know if this expression is correct because I don't find any source to compare it on the internet? | |
| May 12, 2020 at 19:05 | comment | added | Amateur Physicist | So there is no difference between q=$0$ and q=$\frac{\pi}{a}$ since there are both complex and with the same "relaxation time"? | |
| May 12, 2020 at 18:47 | history | answered | Superfast Jellyfish | CC BY-SA 4.0 |