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May 8, 2020 at 21:05 comment added Skipher Ah, you're totally right. Thank you for that.
May 8, 2020 at 20:09 comment added Eli $J^T Q J$ Don’t work J(n,n) and Q(n,1), similarity transformation work just for matrices not for vectors
May 8, 2020 at 20:04 comment added Eli This is how you get the equations of motion with NEWTON method. You start with $m\ddot R=f+f_c$ where $f_c$ are constraint forces, from hier you go to generalized coordinate, to eliminate the constraint force you multiply the equation with $J^T$ . Thus $J^TmJ \ddot q=J^Tf$ The EOM
May 8, 2020 at 18:41 comment added Skipher I recognize the $J$ as a similarity transformation into another coordinate frame. May I ask why $J$ is not multiplied on the right side for $Q$ and $-g$?
May 8, 2020 at 16:12 history edited Eli CC BY-SA 4.0
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May 8, 2020 at 14:16 comment added Eli Please comment why it is wrong? I think it is correct answer
May 8, 2020 at 12:48 history edited Eli CC BY-SA 4.0
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May 8, 2020 at 12:26 history edited Eli CC BY-SA 4.0
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May 8, 2020 at 12:19 history answered Eli CC BY-SA 4.0