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May 8, 2020 at 17:58 vote accept Milarepa
May 8, 2020 at 15:58 history edited Qmechanic
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May 8, 2020 at 15:32 answer added mike stone timeline score: 2
May 8, 2020 at 13:11 comment added Ronan If you have $N$ independent fermions in your system, your Hamiltonian should be of dimension $2^N$, and so should $\mathcal{C}$, no?
May 8, 2020 at 10:03 comment added fra_pero Can you please explain explain the action of $\hat{\mathcal C}$ in more details? What is $U$? I also cannot follow the passages.
May 8, 2020 at 9:43 history asked Milarepa CC BY-SA 4.0