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user258881
user258881

Why does less force correspondscorrespond to less work done?

I'm confused with the definition of work in physics. I know that it's defined as a product of force, displacement and a cosine of angle between them: $W = F * s * cos(\alpha)$$W = F s \cos(\alpha)$. But that means that the work of moving an object from one place to another depends on the absolute value of force we apply to it provided the displacement and the angle stay the same. But as I understood, the work equals to the total energy given away to move the object. But with weaker force and the same distance we will move the object to the finish point just with more time and the energy intuitively should stay the same. So why is that the case that weaker force corresponds to less work done? Thank you.

Why less force corresponds to less work done?

I'm confused with the definition of work in physics. I know that it's defined as a product of force, displacement and a cosine of angle between them: $W = F * s * cos(\alpha)$. But that means that the work of moving an object from one place to another depends on the absolute value of force we apply to it provided the displacement and the angle stay the same. But as I understood, the work equals to the total energy given away to move the object. But with weaker force and the same distance we will move the object to the finish point just with more time and the energy intuitively should stay the same. So why is that the case that weaker force corresponds to less work done? Thank you.

Why does less force correspond to less work done?

I'm confused with the definition of work in physics. I know that it's defined as a product of force, displacement and a cosine of angle between them: $W = F s \cos(\alpha)$. But that means that the work of moving an object from one place to another depends on the absolute value of force we apply to it provided the displacement and the angle stay the same. But as I understood, the work equals to the total energy given away to move the object. But with weaker force and the same distance we will move the object to the finish point just with more time and the energy intuitively should stay the same. So why is that the case that weaker force corresponds to less work done? Thank you.

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DanyloL
DanyloL
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Why less force corresponds to less work done?

I'm confused with the definition of work in physics. I know that it's defined as a product of force, displacement and a cosine of angle between them: $W = F * s * cos(\alpha)$. But that means that the work of moving an object from one place to another depends on the absolute value of force we apply to it provided the displacement and the angle stay the same. But as I understood, the work equals to the total energy given away to move the object. But with weaker force and the same distance we will move the object to the finish point just with more time and the energy intuitively should stay the same. So why is that the case that weaker force corresponds to less work done? Thank you.