Timeline for "A perfectly inelastic collision has a coefficient of 0, but a 0 value does not have to be perfectly inelastic" what does this mean?
Current License: CC BY-SA 4.0
16 events
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| May 6, 2020 at 12:15 | vote | accept | Koustubh Jain | ||
| May 6, 2020 at 12:02 | history | edited | Philip Wood | CC BY-SA 4.0 |
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| May 6, 2020 at 10:13 | history | edited | Philip Wood | CC BY-SA 4.0 |
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| May 6, 2020 at 9:36 | comment | added | Philip Wood | Let us continue this discussion in chat. | |
| May 6, 2020 at 9:30 | comment | added | user262759 | Does total loss of kinetic energy after collision necessarily mean the collision is perfectly inelastic? | |
| May 6, 2020 at 9:20 | comment | added | user262759 | Does coming to the rest after collision necessarily mean the collision is perfectly inelastic? | |
| May 6, 2020 at 9:18 | comment | added | Philip Wood | "No, it is not necessary that they should move opposite to stick together." I am not claiming that bodies have to be moving in opposite directions if they are to stick together! | |
| May 6, 2020 at 9:14 | comment | added | user262759 | No, it is not necessary that they should move in opposite direction to stick together. Suppose one body is moving faster than other body in the same direction then after some time fast moving body collides & sticks to slower body. Sticking may happen also while moving in the same direction. | |
| May 6, 2020 at 9:09 | comment | added | Philip Wood | "Then why did you say that bodies come to rest in perfect inelastic collision?" I said that $in\ the\ centre\ of\ mass\ frame\ of\ reference$ they came to rest. That's because in this frame of reference the bodies had equal and opposite momenta before the collision. | |
| May 6, 2020 at 9:05 | comment | added | Philip Wood | Yes, you are right. Momentum is a vector quantity, so, for example if the bodies are approaching each other, collide and stop, momentum will still be conserved. No momentum after the collision, but none before either, because before the collision the bodies had equal $and\ opposite$ momenta! | |
| May 6, 2020 at 9:01 | comment | added | user262759 | Then why did you say that bodies come to rest in perfect inelastic collision? | |
| May 6, 2020 at 8:58 | comment | added | user262759 | In perfect inelastic collision if two bodies come to rest after collision then how their momentum is conserved? Because momentum must be conserved in any type of collision. Am I right? | |
| May 6, 2020 at 8:46 | history | edited | Philip Wood | CC BY-SA 4.0 |
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| May 6, 2020 at 8:37 | history | edited | Philip Wood | CC BY-SA 4.0 |
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| May 6, 2020 at 8:22 | history | edited | Philip Wood | CC BY-SA 4.0 |
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| May 6, 2020 at 8:16 | history | answered | Philip Wood | CC BY-SA 4.0 |