Timeline for How to calculate the field tensor from a metric?
Current License: CC BY-SA 4.0
13 events
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Oct 15, 2021 at 1:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jun 14, 2021 at 9:07 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jan 28, 2021 at 0:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
May 6, 2020 at 19:54 | comment | added | Cinaed Simson | You should remove the "general relativity" tag and add the "special relativity" tag. | |
May 6, 2020 at 19:48 | comment | added | Cinaed Simson | This post is actually $3$ questions. Since this an EM problem, the space is Minkowski, i.e., the line element in Cartesian is $ds^2 = -dt^2 + dx^2 + dy^2 + dz^2.$ To convert the spatial part of the Minkowsk line element $dx^2 + dy^2 + dz^2$ to spherical coordinates use the spherical coordinate transformation. Regarding the tensor, $B=0$ so you're only left with the projections of the $E(r)$ field on $(x,y,z).$ Either transform the tensor, or transform $E(r)$ to Cartesian coordinates. You can calculate $F_{\mu \nu}$ by either using the metric or the vector potentials in spherical coordinates. | |
May 6, 2020 at 15:13 | answer | added | user87745 | timeline score: 1 | |
May 6, 2020 at 5:30 | answer | added | peek-a-boo | timeline score: 2 | |
May 6, 2020 at 1:11 | review | Close votes | |||
May 8, 2020 at 12:37 | |||||
May 5, 2020 at 23:29 | comment | added | Nick M | My apologies. I've updated the question. | |
May 5, 2020 at 23:27 | history | edited | Nick M | CC BY-SA 4.0 |
added 105 characters in body
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May 5, 2020 at 22:55 | review | First posts | |||
May 6, 2020 at 0:21 | |||||
May 5, 2020 at 22:55 | comment | added | knzhou | Why do you expect that you would be able to recover the EM field tensor from the metric alone? | |
May 5, 2020 at 22:53 | history | asked | Nick M | CC BY-SA 4.0 |