Timeline for Two equivalent supercurrent expressions from Ginzburg-Landau theory?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 1, 2020 at 8:24 | history | edited | user262693 | CC BY-SA 4.0 |
Closure.
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| May 1, 2020 at 8:21 | vote | accept | user262693 | ||
| May 1, 2020 at 8:18 | comment | added | user262693 | It's taken me a shockingly long time to remember that $Im[z] = \frac{1}{2i} (z - z^*)$... I had that rearrangement but just forgot some 6th form calculus... A Google quickly helped that. Thanks for pointing that out! | |
| May 1, 2020 at 8:13 | answer | added | Manuel Algaba | timeline score: 0 | |
| May 1, 2020 at 8:12 | comment | added | Sunyam | It works fine on my mobile app (you have to use render mathjax option). You dont need to split order parameter into phase and amplitude to see the equivalence, observe that second term in the above comment is the complex conjugate of first. | |
| May 1, 2020 at 8:12 | history | edited | user262693 | CC BY-SA 4.0 |
added 140 characters in body
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| May 1, 2020 at 8:09 | comment | added | user262693 | @Sunyam thanks for the comment; I've tried to write it out, but I'm not sure how that helps. I'm currently having a play around with the phase of the order parameter and seeing if I can work something out that way. | |
| May 1, 2020 at 8:07 | comment | added | Sunyam | The last equation you wrote can be rearranged as $\vec{J}_{s}^{} = \frac{1}{2 i}\left[\psi_{}^{*}\left(\vec{\nabla} _{}^{} - i \vec{A} _{}^{}\right) \psi_{}^{} - \psi_{}^{}\left(\vec{\nabla} _{}^{}+ i \vec{A} _{}^{}\right) \psi_{}^{*}\right]$. | |
| May 1, 2020 at 7:55 | review | First posts | |||
| May 1, 2020 at 8:24 | |||||
| May 1, 2020 at 7:50 | history | asked | user262693 | CC BY-SA 4.0 |